Whakaoti i te 9x^2=16

$$9 { x }^{ 2 } =16$$

Whakaoti mō x

$$x = \frac{4}{3} = 1\frac{1}{3} \approx 1.333333333$$

$$x = -\frac{4}{3} = -1\frac{1}{3} \approx -1.333333333$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Whakawehea ngā taha e rua ki te 9.

$$x^{2}=\frac{16}{9}$$

Tangohia te \frac{16}{9} mai i ngā taha e rua.

$$x^{2}-\frac{16}{9}=0$$

Me whakarea ngā taha e rua ki te 9.

$$9x^{2}-16=0$$

Whakaarohia te 9x^{2}-16. Tuhia anō te 9x^{2}-16 hei \left(3x\right)^{2}-4^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(3x-4\right)\left(3x+4\right)=0$$

Hei kimi otinga whārite, me whakaoti te 3x-4=0 me te 3x+4=0.

$$x=\frac{4}{3} x=-\frac{4}{3}$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te 9.

$$x^{2}=\frac{16}{9}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{4}{3} x=-\frac{4}{3}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawehea ngā taha e rua ki te 9.

$$x^{2}=\frac{16}{9}$$

Tangohia te \frac{16}{9} mai i ngā taha e rua.

$$x^{2}-\frac{16}{9}=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -\frac{16}{9} mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-\frac{16}{9}\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-\frac{16}{9}\right)}}{2}$$

Whakareatia -4 ki te -\frac{16}{9}.

$$x=\frac{0±\sqrt{\frac{64}{9}}}{2}$$

Tuhia te pūtakerua o te \frac{64}{9}.

$$x=\frac{0±\frac{8}{3}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±\frac{8}{3}}{2} ina he tāpiri te ±.

$$x=\frac{4}{3}$$

Nā, me whakaoti te whārite x=\frac{0±\frac{8}{3}}{2} ina he tango te ±.

$$x=-\frac{4}{3}$$

Kua oti te whārite te whakatau.

$$x=\frac{4}{3} x=-\frac{4}{3}$$