Whakaoti i te 9+m^2=1+(m+4)^2

$$9 + m ^ { 2 } = 1 + ( m + 4 ) ^ { 2 }$$

Whakaoti mō m

$$m=-1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(m+4\right)^{2}.

$$9+m^{2}=1+m^{2}+8m+16$$

Tāpirihia te 1 ki te 16, ka 17.

$$9+m^{2}=17+m^{2}+8m$$

Tangohia te m^{2} mai i ngā taha e rua.

$$9+m^{2}-m^{2}=17+8m$$

Pahekotia te m^{2} me -m^{2}, ka 0.

$$9=17+8m$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$17+8m=9$$

Tangohia te 17 mai i ngā taha e rua.

$$8m=9-17$$

Tangohia te 17 i te 9, ka -8.

$$8m=-8$$

Whakawehea ngā taha e rua ki te 8.

$$m=\frac{-8}{8}$$

Whakawehea te -8 ki te 8, kia riro ko -1.

$$m=-1$$