Whakaoti i te 8x+2=(5-x)3x

$$8x+2=(5-x)3x$$

Whakaoti mō x

$$x=\frac{1}{3}\approx 0.333333333$$

$$x=2$$

Ngā Upane Whakamahi Tauwehe Mā te Whakarōpū

Whakamahia te āhuatanga tohatoha hei whakarea te 5-x ki te 3.

$$8x+2=\left(15-3x\right)x$$

Whakamahia te āhuatanga tohatoha hei whakarea te 15-3x ki te x.

$$8x+2=15x-3x^{2}$$

Tangohia te 15x mai i ngā taha e rua.

$$8x+2-15x=-3x^{2}$$

Pahekotia te 8x me -15x, ka -7x.

$$-7x+2=-3x^{2}$$

Me tāpiri te 3x^{2} ki ngā taha e rua.

$$-7x+2+3x^{2}=0$$

Hurinahatia te pūrau ki te āhua tānga ngahuru. Whakaraupapahia ngā kīanga tau mai i te pū teitei rawa ki te mea iti rawa.

$$3x^{2}-7x+2=0$$

Hei whakaoti i te whārite, whakatauwehea te taha mauī mā te whakarōpū. Tuatahi, me tuhi anō te taha mauī hei 3x^{2}+ax+bx+2. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=-7 ab=3\times 2=6$$

I te mea kua tōrunga te ab, he ōrite te tohu o a me b. I te mea kua tōraro te a+b, he tōraro hoki a a me b. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua 6.

$$-1,-6 -2,-3$$

Tātaihia te tapeke mō ia takirua.

$$-1-6=-7 -2-3=-5$$

Ko te otinga te takirua ka hoatu i te tapeke -7.

$$a=-6 b=-1$$

Tuhia anō te 3x^{2}-7x+2 hei \left(3x^{2}-6x\right)+\left(-x+2\right).

$$\left(3x^{2}-6x\right)+\left(-x+2\right)$$

Tauwehea te 3x i te tuatahi me te -1 i te rōpū tuarua.

$$3x\left(x-2\right)-\left(x-2\right)$$

Whakatauwehea atu te kīanga pātahi x-2 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(x-2\right)\left(3x-1\right)$$

Hei kimi otinga whārite, me whakaoti te x-2=0 me te 3x-1=0.

$$x=2 x=\frac{1}{3}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakamahia te āhuatanga tohatoha hei whakarea te 5-x ki te 3.

$$8x+2=\left(15-3x\right)x$$

Whakamahia te āhuatanga tohatoha hei whakarea te 15-3x ki te x.

$$8x+2=15x-3x^{2}$$

Tangohia te 15x mai i ngā taha e rua.

$$8x+2-15x=-3x^{2}$$

Pahekotia te 8x me -15x, ka -7x.

$$-7x+2=-3x^{2}$$

Me tāpiri te 3x^{2} ki ngā taha e rua.

$$-7x+2+3x^{2}=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$3x^{2}-7x+2=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 3 mō a, -7 mō b, me 2 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-7\right)±\sqrt{\left(-7\right)^{2}-4\times 3\times 2}}{2\times 3}$$

Pūrua -7.

$$x=\frac{-\left(-7\right)±\sqrt{49-4\times 3\times 2}}{2\times 3}$$

Whakareatia -4 ki te 3.

$$x=\frac{-\left(-7\right)±\sqrt{49-12\times 2}}{2\times 3}$$

Whakareatia -12 ki te 2.

$$x=\frac{-\left(-7\right)±\sqrt{49-24}}{2\times 3}$$

Tāpiri 49 ki te -24.

$$x=\frac{-\left(-7\right)±\sqrt{25}}{2\times 3}$$

Tuhia te pūtakerua o te 25.

$$x=\frac{-\left(-7\right)±5}{2\times 3}$$

Ko te tauaro o -7 ko 7.

$$x=\frac{7±5}{2\times 3}$$

Whakareatia 2 ki te 3.

$$x=\frac{7±5}{6}$$

Nā, me whakaoti te whārite x=\frac{7±5}{6} ina he tāpiri te ±. Tāpiri 7 ki te 5.

$$x=\frac{12}{6}$$

Whakawehe 12 ki te 6.

$$x=2$$

Nā, me whakaoti te whārite x=\frac{7±5}{6} ina he tango te ±. Tango 5 mai i 7.

$$x=\frac{2}{6}$$

Whakahekea te hautanga \frac{2}{6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x=\frac{1}{3}$$

Kua oti te whārite te whakatau.

$$x=2 x=\frac{1}{3}$$

Ngā Upane mō te Whakaoti i te Pūrua

Whakamahia te āhuatanga tohatoha hei whakarea te 5-x ki te 3.

$$8x+2=\left(15-3x\right)x$$

Whakamahia te āhuatanga tohatoha hei whakarea te 15-3x ki te x.

$$8x+2=15x-3x^{2}$$

Tangohia te 15x mai i ngā taha e rua.

$$8x+2-15x=-3x^{2}$$

Pahekotia te 8x me -15x, ka -7x.

$$-7x+2=-3x^{2}$$

Me tāpiri te 3x^{2} ki ngā taha e rua.

$$-7x+2+3x^{2}=0$$

Tangohia te 2 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-7x+3x^{2}=-2$$

Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.

$$3x^{2}-7x=-2$$

Whakawehea ngā taha e rua ki te 3.

$$\frac{3x^{2}-7x}{3}=-\frac{2}{3}$$

Mā te whakawehe ki te 3 ka wetekia te whakareanga ki te 3.

$$x^{2}-\frac{7}{3}x=-\frac{2}{3}$$

Whakawehea te -\frac{7}{3}, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te -\frac{7}{6}. Nā, tāpiria te pūrua o te -\frac{7}{6} ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$x^{2}-\frac{7}{3}x+\left(-\frac{7}{6}\right)^{2}=-\frac{2}{3}+\left(-\frac{7}{6}\right)^{2}$$

Pūruatia -\frac{7}{6} mā te pūrua i te taurunga me te tauraro o te hautanga.

$$x^{2}-\frac{7}{3}x+\frac{49}{36}=-\frac{2}{3}+\frac{49}{36}$$

Tāpiri -\frac{2}{3} ki te \frac{49}{36} mā te kimi i te tauraro pātahi me te tāpiri i ngā taurunga. Ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$x^{2}-\frac{7}{3}x+\frac{49}{36}=\frac{25}{36}$$

Tauwehea x^{2}-\frac{7}{3}x+\frac{49}{36}. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{7}{6}\right)^{2}=\frac{25}{36}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x-\frac{7}{6}\right)^{2}}=\sqrt{\frac{25}{36}}$$

Whakarūnātia.

$$x-\frac{7}{6}=\frac{5}{6} x-\frac{7}{6}=-\frac{5}{6}$$

Me tāpiri \frac{7}{6} ki ngā taha e rua o te whārite.

$$x=2 x=\frac{1}{3}$$