Whakaoti i te 80(x+1)^2=1352

$$80 ( x + 1 ) ^ { 2 } = 1352$$

Whakaoti mō x

$$x=\frac{13\sqrt{10}}{10}-1\approx 3.110960958$$

$$x=-\frac{13\sqrt{10}}{10}-1\approx -5.110960958$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te 80.

$$\frac{80\left(x+1\right)^{2}}{80}=\frac{1352}{80}$$

Mā te whakawehe ki te 80 ka wetekia te whakareanga ki te 80.

$$\left(x+1\right)^{2}=\frac{1352}{80}$$

Whakahekea te hautanga \frac{1352}{80} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 8.

$$\left(x+1\right)^{2}=\frac{169}{10}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x+1=\frac{13\sqrt{10}}{10} x+1=-\frac{13\sqrt{10}}{10}$$

Me tango 1 mai i ngā taha e rua o te whārite.

$$x+1-1=\frac{13\sqrt{10}}{10}-1 x+1-1=-\frac{13\sqrt{10}}{10}-1$$

Mā te tango i te 1 i a ia ake anō ka toe ko te 0.

$$x=\frac{13\sqrt{10}}{10}-1 x=-\frac{13\sqrt{10}}{10}-1$$