Whakaoti i te 8(x-9)-9(x-8)=x+8-(x-4)

$$8(x-9)-9(x-8)=x+8-(x-4)$$

Whakaoti mō x

$$x=-12$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 8 ki te x-9.

$$8x-72-9\left(x-8\right)=x+8-\left(x-4\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -9 ki te x-8.

$$8x-72-9x+72=x+8-\left(x-4\right)$$

Pahekotia te 8x me -9x, ka -x.

$$-x-72+72=x+8-\left(x-4\right)$$

Tāpirihia te -72 ki te 72, ka 0.

$$-x=x+8-\left(x-4\right)$$

Hei kimi i te tauaro o x-4, kimihia te tauaro o ia taurangi.

$$-x=x+8-x-\left(-4\right)$$

Ko te tauaro o -4 ko 4.

$$-x=x+8-x+4$$

Pahekotia te x me -x, ka 0.

$$-x=8+4$$

Tāpirihia te 8 ki te 4, ka 12.

$$-x=12$$

Me whakarea ngā taha e rua ki te -1.

$$x=-12$$