Whakaoti i te 8(x-4)+3xleq2(x-1)+10

$$8(x-4)+3x \leq 2(x-1)+10$$

Whakaoti mō x

$$x\leq \frac{40}{9}$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te 8 ki te x-4.

$$8x-32+3x\leq 2\left(x-1\right)+10$$

Pahekotia te 8x me 3x, ka 11x.

$$11x-32\leq 2\left(x-1\right)+10$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te x-1.

$$11x-32\leq 2x-2+10$$

Tāpirihia te -2 ki te 10, ka 8.

$$11x-32\leq 2x+8$$

Tangohia te 2x mai i ngā taha e rua.

$$11x-32-2x\leq 8$$

Pahekotia te 11x me -2x, ka 9x.

$$9x-32\leq 8$$

Me tāpiri te 32 ki ngā taha e rua.

$$9x\leq 8+32$$

Tāpirihia te 8 ki te 32, ka 40.

$$9x\leq 40$$

Whakawehea ngā taha e rua ki te 9. I te mea he tōrunga te 9, kāore e huri te ahunga koreōrite.

$$x\leq \frac{40}{9}$$