Whakaoti i te 8xy-2y=3

$$8 x y - 2 y = 3$$

Whakaoti mō x

$$x=\frac{1}{4}+\frac{3}{8y}$$

$$y\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me tāpiri te 2y ki ngā taha e rua.

$$8xy=3+2y$$

He hanga arowhānui tō te whārite.

$$8yx=2y+3$$

Whakawehea ngā taha e rua ki te 8y.

$$\frac{8yx}{8y}=\frac{2y+3}{8y}$$

Mā te whakawehe ki te 8y ka wetekia te whakareanga ki te 8y.

$$x=\frac{2y+3}{8y}$$

Whakawehe 3+2y ki te 8y.

$$x=\frac{1}{4}+\frac{3}{8y}$$

Whakaoti mō y

$$y=\frac{3}{2\left(4x-1\right)}$$

$$x\neq \frac{1}{4}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(8x-2\right)y=3$$

Whakawehea ngā taha e rua ki te 8x-2.

$$\frac{\left(8x-2\right)y}{8x-2}=\frac{3}{8x-2}$$

Mā te whakawehe ki te 8x-2 ka wetekia te whakareanga ki te 8x-2.

$$y=\frac{3}{8x-2}$$

Whakawehe 3 ki te 8x-2.

$$y=\frac{3}{2\left(4x-1\right)}$$