Whakaoti i te 8x^2-4x+16=

$$8 x ^ { 2 } - 4 x + 16 =$$

Tauwehe

$$4\left(2x^{2}-x+4\right)$$

Ngā Upane Otinga

Tauwehea te 4. Kāore te pūrau 2x^{2}-x+4 i whakatauwehea i te mea kāhore ōna pūtake whakahau.

$$4\left(2x^{2}-x+4\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$8x^{2}-4x+16=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-\left(-4\right)±\sqrt{\left(-4\right)^{2}-4\times 8\times 16}}{2\times 8}$$

Pūrua -4.

$$x=\frac{-\left(-4\right)±\sqrt{16-4\times 8\times 16}}{2\times 8}$$

Whakareatia -4 ki te 8.

$$x=\frac{-\left(-4\right)±\sqrt{16-32\times 16}}{2\times 8}$$

Whakareatia -32 ki te 16.

$$x=\frac{-\left(-4\right)±\sqrt{16-512}}{2\times 8}$$

Tāpiri 16 ki te -512.

$$x=\frac{-\left(-4\right)±\sqrt{-496}}{2\times 8}$$

Tā te mea e kore te pūrua o tētahi tau tōraro e tautohutia ki te āpure tūturu, kāhore he rongoā. Kāore e taea te pūrau pūrua te whakatauwehe.

$$8x^{2}-4x+16$$

Aromātai

$$8x^{2}-4x+16$$