Whakaoti i te 8x^2-14=-11

$$8 x ^ { 2 } - 14 = - 11$$

Whakaoti mō x

$$x=\frac{\sqrt{6}}{4}\approx 0.612372436$$

$$x=-\frac{\sqrt{6}}{4}\approx -0.612372436$$

Ngā Upane mā te Kimi Pūtakerua

Me tāpiri te 14 ki ngā taha e rua.

$$8x^{2}=-11+14$$

Tāpirihia te -11 ki te 14, ka 3.

$$8x^{2}=3$$

Whakawehea ngā taha e rua ki te 8.

$$x^{2}=\frac{3}{8}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{\sqrt{6}}{4} x=-\frac{\sqrt{6}}{4}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Me tāpiri te 11 ki ngā taha e rua.

$$8x^{2}-14+11=0$$

Tāpirihia te -14 ki te 11, ka -3.

$$8x^{2}-3=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 8 mō a, 0 mō b, me -3 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 8\left(-3\right)}}{2\times 8}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 8\left(-3\right)}}{2\times 8}$$

Whakareatia -4 ki te 8.

$$x=\frac{0±\sqrt{-32\left(-3\right)}}{2\times 8}$$

Whakareatia -32 ki te -3.

$$x=\frac{0±\sqrt{96}}{2\times 8}$$

Tuhia te pūtakerua o te 96.

$$x=\frac{0±4\sqrt{6}}{2\times 8}$$

Whakareatia 2 ki te 8.

$$x=\frac{0±4\sqrt{6}}{16}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{6}}{16} ina he tāpiri te ±.

$$x=\frac{\sqrt{6}}{4}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{6}}{16} ina he tango te ±.

$$x=-\frac{\sqrt{6}}{4}$$

Kua oti te whārite te whakatau.

$$x=\frac{\sqrt{6}}{4} x=-\frac{\sqrt{6}}{4}$$