Whakaoti i te 8x^2+14x+5

$$8 x ^ { 2 } + 14 x + 5$$

Tauwehe

$$\left(2x+1\right)\left(4x+5\right)$$

Ngā Upane Otinga

Whakatauwehea te kīanga mā te whakarōpū. Tuatahi, me tuhi anō te kīanga hei 8x^{2}+ax+bx+5. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=14 ab=8\times 5=40$$

I te mea kua tōrunga te ab, he ōrite te tohu o a me b. I te mea kua tōrunga te a+b, he tōrunga hoki a a me b. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua 40.

$$1,40 2,20 4,10 5,8$$

Tātaihia te tapeke mō ia takirua.

$$1+40=41 2+20=22 4+10=14 5+8=13$$

Ko te otinga te takirua ka hoatu i te tapeke 14.

$$a=4 b=10$$

Tuhia anō te 8x^{2}+14x+5 hei \left(8x^{2}+4x\right)+\left(10x+5\right).

$$\left(8x^{2}+4x\right)+\left(10x+5\right)$$

Tauwehea te 4x i te tuatahi me te 5 i te rōpū tuarua.

$$4x\left(2x+1\right)+5\left(2x+1\right)$$

Whakatauwehea atu te kīanga pātahi 2x+1 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(2x+1\right)\left(4x+5\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$8x^{2}+14x+5=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-14±\sqrt{14^{2}-4\times 8\times 5}}{2\times 8}$$

Pūrua 14.

$$x=\frac{-14±\sqrt{196-4\times 8\times 5}}{2\times 8}$$

Whakareatia -4 ki te 8.

$$x=\frac{-14±\sqrt{196-32\times 5}}{2\times 8}$$

Whakareatia -32 ki te 5.

$$x=\frac{-14±\sqrt{196-160}}{2\times 8}$$

Tāpiri 196 ki te -160.

$$x=\frac{-14±\sqrt{36}}{2\times 8}$$

Tuhia te pūtakerua o te 36.

$$x=\frac{-14±6}{2\times 8}$$

Whakareatia 2 ki te 8.

$$x=\frac{-14±6}{16}$$

Nā, me whakaoti te whārite x=\frac{-14±6}{16} ina he tāpiri te ±. Tāpiri -14 ki te 6.

$$x=-\frac{8}{16}$$

Whakahekea te hautanga \frac{-8}{16} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 8.

$$x=-\frac{1}{2}$$

Nā, me whakaoti te whārite x=\frac{-14±6}{16} ina he tango te ±. Tango 6 mai i -14.

$$x=-\frac{20}{16}$$

Whakahekea te hautanga \frac{-20}{16} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 4.

$$x=-\frac{5}{4}$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te -\frac{1}{2} mō te x_{1} me te -\frac{5}{4} mō te x_{2}.

$$8x^{2}+14x+5=8\left(x-\left(-\frac{1}{2}\right)\right)\left(x-\left(-\frac{5}{4}\right)\right)$$

Whakamāmātia ngā kīanga katoa o te āhua p-\left(-q\right) ki te p+q.

$$8x^{2}+14x+5=8\left(x+\frac{1}{2}\right)\left(x+\frac{5}{4}\right)$$

Tāpiri \frac{1}{2} ki te x mā te kimi i te tauraro pātahi me te tāpiri i ngā taurunga. Ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$8x^{2}+14x+5=8\times \frac{2x+1}{2}\left(x+\frac{5}{4}\right)$$

Tāpiri \frac{5}{4} ki te x mā te kimi i te tauraro pātahi me te tāpiri i ngā taurunga. Ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$8x^{2}+14x+5=8\times \frac{2x+1}{2}\times \frac{4x+5}{4}$$

Whakareatia \frac{2x+1}{2} ki te \frac{4x+5}{4} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro, ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$8x^{2}+14x+5=8\times \frac{\left(2x+1\right)\left(4x+5\right)}{2\times 4}$$

Whakareatia 2 ki te 4.

$$8x^{2}+14x+5=8\times \frac{\left(2x+1\right)\left(4x+5\right)}{8}$$

Whakakorea atu te tauwehe pūnoa nui rawa 8 i roto i te 8 me te 8.

$$8x^{2}+14x+5=\left(2x+1\right)\left(4x+5\right)$$

Aromātai

$$\left(2x+1\right)\left(4x+5\right)$$