Whakaoti i te 8(x+1)^2=7

$$8 ( x + 1 ) ^ { 2 } = 7$$

Whakaoti mō x

$$x=\frac{\sqrt{14}}{4}-1\approx -0.064585653$$

$$x=-\frac{\sqrt{14}}{4}-1\approx -1.935414347$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te 8.

$$\frac{8\left(x+1\right)^{2}}{8}=\frac{7}{8}$$

Mā te whakawehe ki te 8 ka wetekia te whakareanga ki te 8.

$$\left(x+1\right)^{2}=\frac{7}{8}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x+1=\frac{\sqrt{14}}{4} x+1=-\frac{\sqrt{14}}{4}$$

Me tango 1 mai i ngā taha e rua o te whārite.

$$x+1-1=\frac{\sqrt{14}}{4}-1 x+1-1=-\frac{\sqrt{14}}{4}-1$$

Mā te tango i te 1 i a ia ake anō ka toe ko te 0.

$$x=\frac{\sqrt{14}}{4}-1 x=-\frac{\sqrt{14}}{4}-1$$