Whakaoti i te 8(x+1)+1^2<3(2x)-1

$$8 ( x + 1 ) + 1 ^ { 2 } < 3 ( 2 x ) - 1$$

Whakaoti mō x

$$x<-5$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te 8 ki te x+1.

$$8x+8+1^{2}<3\times 2x-1$$

Tātaihia te 1 mā te pū o 2, kia riro ko 1.

$$8x+8+1<3\times 2x-1$$

Tāpirihia te 8 ki te 1, ka 9.

$$8x+9<3\times 2x-1$$

Whakareatia te 3 ki te 2, ka 6.

$$8x+9<6x-1$$

Tangohia te 6x mai i ngā taha e rua.

$$8x+9-6x<-1$$

Pahekotia te 8x me -6x, ka 2x.

$$2x+9<-1$$

Tangohia te 9 mai i ngā taha e rua.

$$2x<-1-9$$

Tangohia te 9 i te -1, ka -10.

$$2x<-10$$

Whakawehea ngā taha e rua ki te 2. I te mea he tōrunga te 2, kāore e huri te ahunga koreōrite.

$$x<\frac{-10}{2}$$

Whakawehea te -10 ki te 2, kia riro ko -5.

$$x<-5$$