Whakaoti i te 8^2+18^2=B^2

$$8 ^ { 2 } + 18 ^ { 2 } = B ^ { 2 }$$

Whakaoti mō B

$$B=2\sqrt{97}\approx 19.697715604$$

$$B=-2\sqrt{97}\approx -19.697715604$$

Ngā Upane mā te Kimi Pūtakerua

Tātaihia te 8 mā te pū o 2, kia riro ko 64.

$$64+18^{2}=B^{2}$$

Tātaihia te 18 mā te pū o 2, kia riro ko 324.

$$64+324=B^{2}$$

Tāpirihia te 64 ki te 324, ka 388.

$$388=B^{2}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$B^{2}=388$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$B=2\sqrt{97} B=-2\sqrt{97}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tātaihia te 8 mā te pū o 2, kia riro ko 64.

$$64+18^{2}=B^{2}$$

Tātaihia te 18 mā te pū o 2, kia riro ko 324.

$$64+324=B^{2}$$

Tāpirihia te 64 ki te 324, ka 388.

$$388=B^{2}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$B^{2}=388$$

Tangohia te 388 mai i ngā taha e rua.

$$B^{2}-388=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -388 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$B=\frac{0±\sqrt{0^{2}-4\left(-388\right)}}{2}$$

Pūrua 0.

$$B=\frac{0±\sqrt{-4\left(-388\right)}}{2}$$

Whakareatia -4 ki te -388.

$$B=\frac{0±\sqrt{1552}}{2}$$

Tuhia te pūtakerua o te 1552.

$$B=\frac{0±4\sqrt{97}}{2}$$

Nā, me whakaoti te whārite B=\frac{0±4\sqrt{97}}{2} ina he tāpiri te ±.

$$B=2\sqrt{97}$$

Nā, me whakaoti te whārite B=\frac{0±4\sqrt{97}}{2} ina he tango te ±.

$$B=-2\sqrt{97}$$

Kua oti te whārite te whakatau.

$$B=2\sqrt{97} B=-2\sqrt{97}$$