Whakaoti i te 7x-5y(x+36y)=7

$$7x-5y(x+36y)=7$$

Whakaoti mō x

$$x=\frac{180y^{2}+7}{7-5y}$$

$$y\neq \frac{7}{5}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te -1 ki te 5, ka -5.

$$7x-5y\left(x+36y\right)=7$$

Whakamahia te āhuatanga tohatoha hei whakarea te -5y ki te x+36y.

$$7x-5yx-180y^{2}=7$$

Me tāpiri te 180y^{2} ki ngā taha e rua.

$$7x-5yx=7+180y^{2}$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(7-5y\right)x=7+180y^{2}$$

He hanga arowhānui tō te whārite.

$$\left(7-5y\right)x=180y^{2}+7$$

Whakawehea ngā taha e rua ki te -5y+7.

$$\frac{\left(7-5y\right)x}{7-5y}=\frac{180y^{2}+7}{7-5y}$$

Mā te whakawehe ki te -5y+7 ka wetekia te whakareanga ki te -5y+7.

$$x=\frac{180y^{2}+7}{7-5y}$$

Whakaoti mō y (complex solution)

$$y=\frac{\sqrt{25x^{2}+5040x-5040}}{360}-\frac{x}{72}$$

$$y=-\frac{\sqrt{25x^{2}+5040x-5040}}{360}-\frac{x}{72}$$

Whakaoti mō y

$$y=\frac{\sqrt{25x^{2}+5040x-5040}}{360}-\frac{x}{72}$$

$$y=-\frac{\sqrt{25x^{2}+5040x-5040}}{360}-\frac{x}{72}\text{, }x\geq \frac{12\sqrt{1799}-504}{5}\text{ or }x\leq \frac{-12\sqrt{1799}-504}{5}$$