Whakaoti i te 7-{x+[4-(3x+1)]}=x+4

$$7 - \{ x + [ 4 - ( 3 x + 1 ) ] \} = x + 4$$

Whakaoti mō x

$$x=0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Hei kimi i te tauaro o 3x+1, kimihia te tauaro o ia taurangi.

$$7-\left(x+4-3x-1\right)=x+4$$

Pahekotia te x me -3x, ka -2x.

$$7-\left(-2x+4-1\right)=x+4$$

Tangohia te 1 i te 4, ka 3.

$$7-\left(-2x+3\right)=x+4$$

Hei kimi i te tauaro o -2x+3, kimihia te tauaro o ia taurangi.

$$7-\left(-2x\right)-3=x+4$$

Ko te tauaro o -2x ko 2x.

$$7+2x-3=x+4$$

Tangohia te 3 i te 7, ka 4.

$$4+2x=x+4$$

Tangohia te x mai i ngā taha e rua.

$$4+2x-x=4$$

Pahekotia te 2x me -x, ka x.

$$4+x=4$$

Tangohia te 4 mai i ngā taha e rua.

$$x=4-4$$

Tangohia te 4 i te 4, ka 0.

$$x=0$$