Whakaoti i te 7-[8x-3(x+3)]=5x-(4-2x)

$$7 - [ 8 x - 3 ( x + 3 ) ] = 5 x - ( 4 - 2 x )$$

Whakaoti mō x

$$x = \frac{5}{3} = 1\frac{2}{3} \approx 1.666666667$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te x+3.

$$7-\left(8x-3x-9\right)=5x-\left(4-2x\right)$$

Pahekotia te 8x me -3x, ka 5x.

$$7-\left(5x-9\right)=5x-\left(4-2x\right)$$

Hei kimi i te tauaro o 5x-9, kimihia te tauaro o ia taurangi.

$$7-5x-\left(-9\right)=5x-\left(4-2x\right)$$

Ko te tauaro o -9 ko 9.

$$7-5x+9=5x-\left(4-2x\right)$$

Tāpirihia te 7 ki te 9, ka 16.

$$16-5x=5x-\left(4-2x\right)$$

Hei kimi i te tauaro o 4-2x, kimihia te tauaro o ia taurangi.

$$16-5x=5x-4-\left(-2x\right)$$

Ko te tauaro o -2x ko 2x.

$$16-5x=5x-4+2x$$

Pahekotia te 5x me 2x, ka 7x.

$$16-5x=7x-4$$

Tangohia te 7x mai i ngā taha e rua.

$$16-5x-7x=-4$$

Pahekotia te -5x me -7x, ka -12x.

$$16-12x=-4$$

Tangohia te 16 mai i ngā taha e rua.

$$-12x=-4-16$$

Tangohia te 16 i te -4, ka -20.

$$-12x=-20$$

Whakawehea ngā taha e rua ki te -12.

$$x=\frac{-20}{-12}$$

Whakahekea te hautanga \frac{-20}{-12} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -4.

$$x=\frac{5}{3}$$