Whakaoti i te 64+25-AC^2=40

$$64 + 25 - A C ^ { 2 } = 40$$

Whakaoti mō A

$$A=\frac{49}{C^{2}}$$

$$C\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tāpirihia te 64 ki te 25, ka 89.

$$89-AC^{2}=40$$

Tangohia te 89 mai i ngā taha e rua.

$$-AC^{2}=40-89$$

Tangohia te 89 i te 40, ka -49.

$$-AC^{2}=-49$$

He hanga arowhānui tō te whārite.

$$\left(-C^{2}\right)A=-49$$

Whakawehea ngā taha e rua ki te -C^{2}.

$$\frac{\left(-C^{2}\right)A}{-C^{2}}=-\frac{49}{-C^{2}}$$

Mā te whakawehe ki te -C^{2} ka wetekia te whakareanga ki te -C^{2}.

$$A=-\frac{49}{-C^{2}}$$

Whakawehe -49 ki te -C^{2}.

$$A=\frac{49}{C^{2}}$$

Whakaoti mō C (complex solution)

$$C=-7A^{-\frac{1}{2}}$$

$$C=7A^{-\frac{1}{2}}\text{, }A\neq 0$$

Whakaoti mō C

$$C=\frac{7}{\sqrt{A}}$$

$$C=-\frac{7}{\sqrt{A}}\text{, }A>0$$