Whakaoti i te 60(1-t)^2=48.6

$$60 ( 1 - t ) ^ { 2 } = 48.6$$

Whakaoti mō t

$$t=0.1$$

$$t=1.9$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te 60.

$$\frac{60\left(-t+1\right)^{2}}{60}=\frac{48.6}{60}$$

Mā te whakawehe ki te 60 ka wetekia te whakareanga ki te 60.

$$\left(-t+1\right)^{2}=\frac{48.6}{60}$$

Whakawehe 48.6 ki te 60.

$$\left(-t+1\right)^{2}=0.81$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$-t+1=\frac{9}{10} -t+1=-\frac{9}{10}$$

Me tango 1 mai i ngā taha e rua o te whārite.

$$-t+1-1=\frac{9}{10}-1 -t+1-1=-\frac{9}{10}-1$$

Mā te tango i te 1 i a ia ake anō ka toe ko te 0.

$$-t=\frac{9}{10}-1 -t=-\frac{9}{10}-1$$

Tango 1 mai i \frac{9}{10}.

$$-t=-\frac{1}{10}$$

Tango 1 mai i -\frac{9}{10}.

$$-t=-\frac{19}{10}$$

Whakawehea ngā taha e rua ki te -1.

$$\frac{-t}{-1}=-\frac{\frac{1}{10}}{-1} \frac{-t}{-1}=-\frac{\frac{19}{10}}{-1}$$

Mā te whakawehe ki te -1 ka wetekia te whakareanga ki te -1.

$$t=-\frac{\frac{1}{10}}{-1} t=-\frac{\frac{19}{10}}{-1}$$

Whakawehe -\frac{1}{10} ki te -1.

$$t=\frac{1}{10}$$

Whakawehe -\frac{19}{10} ki te -1.

$$t=\frac{19}{10}$$

Kua oti te whārite te whakatau.

$$t=\frac{1}{10} t=\frac{19}{10}$$