Whakaoti i te 6-3(x-2)=4x-(x+8)

$$6-3(x-2)=4x-(x+8)$$

Whakaoti mō x

$$x = \frac{10}{3} = 3\frac{1}{3} \approx 3.333333333$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te x-2.

$$6-3x+6=4x-\left(x+8\right)$$

Tāpirihia te 6 ki te 6, ka 12.

$$12-3x=4x-\left(x+8\right)$$

Hei kimi i te tauaro o x+8, kimihia te tauaro o ia taurangi.

$$12-3x=4x-x-8$$

Pahekotia te 4x me -x, ka 3x.

$$12-3x=3x-8$$

Tangohia te 3x mai i ngā taha e rua.

$$12-3x-3x=-8$$

Pahekotia te -3x me -3x, ka -6x.

$$12-6x=-8$$

Tangohia te 12 mai i ngā taha e rua.

$$-6x=-8-12$$

Tangohia te 12 i te -8, ka -20.

$$-6x=-20$$

Whakawehea ngā taha e rua ki te -6.

$$x=\frac{-20}{-6}$$

Whakahekea te hautanga \frac{-20}{-6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -2.

$$x=\frac{10}{3}$$