Whakaoti i te 6-(1-2x)+x(4-x)=1-x(2+x)

$$6-(1-2x)+x(4-x)=1-x(2+x)$$

Whakaoti mō x

$$x=-\frac{1}{2}=-0.5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Hei kimi i te tauaro o 1-2x, kimihia te tauaro o ia taurangi.

$$6-1-\left(-2x\right)+x\left(4-x\right)=1-x\left(2+x\right)$$

Ko te tauaro o -2x ko 2x.

$$6-1+2x+x\left(4-x\right)=1-x\left(2+x\right)$$

Tangohia te 1 i te 6, ka 5.

$$5+2x+x\left(4-x\right)=1-x\left(2+x\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te 4-x.

$$5+2x+4x-x^{2}=1-x\left(2+x\right)$$

Pahekotia te 2x me 4x, ka 6x.

$$5+6x-x^{2}=1-x\left(2+x\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te 2+x.

$$5+6x-x^{2}=1-\left(2x+x^{2}\right)$$

Hei kimi i te tauaro o 2x+x^{2}, kimihia te tauaro o ia taurangi.

$$5+6x-x^{2}=1-2x-x^{2}$$

Me tāpiri te 2x ki ngā taha e rua.

$$5+6x-x^{2}+2x=1-x^{2}$$

Pahekotia te 6x me 2x, ka 8x.

$$5+8x-x^{2}=1-x^{2}$$

Me tāpiri te x^{2} ki ngā taha e rua.

$$5+8x-x^{2}+x^{2}=1$$

Pahekotia te -x^{2} me x^{2}, ka 0.

$$5+8x=1$$

Tangohia te 5 mai i ngā taha e rua.

$$8x=1-5$$

Tangohia te 5 i te 1, ka -4.

$$8x=-4$$

Whakawehea ngā taha e rua ki te 8.

$$x=\frac{-4}{8}$$

Whakahekea te hautanga \frac{-4}{8} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 4.

$$x=-\frac{1}{2}$$