Whakaoti i te 6z^2-13z+6

$$6 z ^ { 2 } - 13 z + 6$$

Tauwehe

$$\left(2z-3\right)\left(3z-2\right)$$

Ngā Upane Otinga

Whakatauwehea te kīanga mā te whakarōpū. Tuatahi, me tuhi anō te kīanga hei 6z^{2}+az+bz+6. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=-13 ab=6\times 6=36$$

I te mea kua tōrunga te ab, he ōrite te tohu o a me b. I te mea kua tōraro te a+b, he tōraro hoki a a me b. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua 36.

$$-1,-36 -2,-18 -3,-12 -4,-9 -6,-6$$

Tātaihia te tapeke mō ia takirua.

$$-1-36=-37 -2-18=-20 -3-12=-15 -4-9=-13 -6-6=-12$$

Ko te otinga te takirua ka hoatu i te tapeke -13.

$$a=-9 b=-4$$

Tuhia anō te 6z^{2}-13z+6 hei \left(6z^{2}-9z\right)+\left(-4z+6\right).

$$\left(6z^{2}-9z\right)+\left(-4z+6\right)$$

Tauwehea te 3z i te tuatahi me te -2 i te rōpū tuarua.

$$3z\left(2z-3\right)-2\left(2z-3\right)$$

Whakatauwehea atu te kīanga pātahi 2z-3 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(2z-3\right)\left(3z-2\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$6z^{2}-13z+6=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$z=\frac{-\left(-13\right)±\sqrt{\left(-13\right)^{2}-4\times 6\times 6}}{2\times 6}$$

Pūrua -13.

$$z=\frac{-\left(-13\right)±\sqrt{169-4\times 6\times 6}}{2\times 6}$$

Whakareatia -4 ki te 6.

$$z=\frac{-\left(-13\right)±\sqrt{169-24\times 6}}{2\times 6}$$

Whakareatia -24 ki te 6.

$$z=\frac{-\left(-13\right)±\sqrt{169-144}}{2\times 6}$$

Tāpiri 169 ki te -144.

$$z=\frac{-\left(-13\right)±\sqrt{25}}{2\times 6}$$

Tuhia te pūtakerua o te 25.

$$z=\frac{-\left(-13\right)±5}{2\times 6}$$

Ko te tauaro o -13 ko 13.

$$z=\frac{13±5}{2\times 6}$$

Whakareatia 2 ki te 6.

$$z=\frac{13±5}{12}$$

Nā, me whakaoti te whārite z=\frac{13±5}{12} ina he tāpiri te ±. Tāpiri 13 ki te 5.

$$z=\frac{18}{12}$$

Whakahekea te hautanga \frac{18}{12} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 6.

$$z=\frac{3}{2}$$

Nā, me whakaoti te whārite z=\frac{13±5}{12} ina he tango te ±. Tango 5 mai i 13.

$$z=\frac{8}{12}$$

Whakahekea te hautanga \frac{8}{12} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 4.

$$z=\frac{2}{3}$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te \frac{3}{2} mō te x_{1} me te \frac{2}{3} mō te x_{2}.

$$6z^{2}-13z+6=6\left(z-\frac{3}{2}\right)\left(z-\frac{2}{3}\right)$$

Tango \frac{3}{2} mai i z mā te kimi i te tauraro pātahi me te tango i ngā taurunga, ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$6z^{2}-13z+6=6\times \frac{2z-3}{2}\left(z-\frac{2}{3}\right)$$

Tango \frac{2}{3} mai i z mā te kimi i te tauraro pātahi me te tango i ngā taurunga, ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$6z^{2}-13z+6=6\times \frac{2z-3}{2}\times \frac{3z-2}{3}$$

Whakareatia \frac{2z-3}{2} ki te \frac{3z-2}{3} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro, ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$6z^{2}-13z+6=6\times \frac{\left(2z-3\right)\left(3z-2\right)}{2\times 3}$$

Whakareatia 2 ki te 3.

$$6z^{2}-13z+6=6\times \frac{\left(2z-3\right)\left(3z-2\right)}{6}$$

Whakakorea atu te tauwehe pūnoa nui rawa 6 i roto i te 6 me te 6.

$$6z^{2}-13z+6=\left(2z-3\right)\left(3z-2\right)$$

Aromātai

$$\left(2z-3\right)\left(3z-2\right)$$