Whakaoti i te 6a^2+8b+6=0

$$6 a ^ { 2 } + 8 b + 6 = 0$$

Whakaoti mō b

$$b=\frac{-3a^{2}-3}{4}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 6a^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$8b+6=-6a^{2}$$

Tangohia te 6 mai i ngā taha e rua.

$$8b=-6a^{2}-6$$

Whakawehea ngā taha e rua ki te 8.

$$\frac{8b}{8}=\frac{-6a^{2}-6}{8}$$

Mā te whakawehe ki te 8 ka wetekia te whakareanga ki te 8.

$$b=\frac{-6a^{2}-6}{8}$$

Whakawehe -6a^{2}-6 ki te 8.

$$b=\frac{-3a^{2}-3}{4}$$

Whakaoti mō a (complex solution)

$$a=-\frac{\sqrt{-12b-9}}{3}$$

$$a=\frac{\sqrt{-12b-9}}{3}$$

Whakaoti mō a

$$a=\frac{\sqrt{-12b-9}}{3}$$

$$a=-\frac{\sqrt{-12b-9}}{3}\text{, }b\leq -\frac{3}{4}$$