Whakaoti i te 6-2(x+1)leq3(1-2x)

$$6 - 2 ( x + 1 ) \leq 3 ( 1 - 2 x )$$

Whakaoti mō x

$$x\leq -\frac{1}{4}$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te x+1.

$$6-2x-2\leq 3\left(1-2x\right)$$

Tangohia te 2 i te 6, ka 4.

$$4-2x\leq 3\left(1-2x\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te 1-2x.

$$4-2x\leq 3-6x$$

Me tāpiri te 6x ki ngā taha e rua.

$$4-2x+6x\leq 3$$

Pahekotia te -2x me 6x, ka 4x.

$$4+4x\leq 3$$

Tangohia te 4 mai i ngā taha e rua.

$$4x\leq 3-4$$

Tangohia te 4 i te 3, ka -1.

$$4x\leq -1$$

Whakawehea ngā taha e rua ki te 4. I te mea he tōrunga te 4, kāore e huri te ahunga koreōrite.

$$x\leq -\frac{1}{4}$$