Whakaoti i te 6(1/2x+1)-7=-3(-1/2x-1)

$$6 ( \frac { 1 } { 2 } x + 1 ) - 7 = - 3 ( - \frac { 1 } { 2 } x - 1 )$$

Whakaoti mō x

$$x = \frac{8}{3} = 2\frac{2}{3} \approx 2.666666667$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 6 ki te \frac{1}{2}x+1.

$$6\times \frac{1}{2}x+6-7=-3\left(-\frac{1}{2}x-1\right)$$

Whakareatia te 6 ki te \frac{1}{2}, ka \frac{6}{2}.

$$\frac{6}{2}x+6-7=-3\left(-\frac{1}{2}x-1\right)$$

Whakawehea te 6 ki te 2, kia riro ko 3.

$$3x+6-7=-3\left(-\frac{1}{2}x-1\right)$$

Tangohia te 7 i te 6, ka -1.

$$3x-1=-3\left(-\frac{1}{2}x-1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te -\frac{1}{2}x-1.

$$3x-1=-3\left(-\frac{1}{2}\right)x+3$$

Tuhia te -3\left(-\frac{1}{2}\right) hei hautanga kotahi.

$$3x-1=\frac{-3\left(-1\right)}{2}x+3$$

Whakareatia te -3 ki te -1, ka 3.

$$3x-1=\frac{3}{2}x+3$$

Tangohia te \frac{3}{2}x mai i ngā taha e rua.

$$3x-1-\frac{3}{2}x=3$$

Pahekotia te 3x me -\frac{3}{2}x, ka \frac{3}{2}x.

$$\frac{3}{2}x-1=3$$

Me tāpiri te 1 ki ngā taha e rua.

$$\frac{3}{2}x=3+1$$

Tāpirihia te 3 ki te 1, ka 4.

$$\frac{3}{2}x=4$$

Me whakarea ngā taha e rua ki te \frac{2}{3}, te tau utu o \frac{3}{2}.

$$x=4\times \frac{2}{3}$$

Tuhia te 4\times \frac{2}{3} hei hautanga kotahi.

$$x=\frac{4\times 2}{3}$$

Whakareatia te 4 ki te 2, ka 8.

$$x=\frac{8}{3}$$