Whakaoti i te 6x^3+4+2x^2*15+x^2

$$6 { x }^{ 3 } +4+2 { x }^{ 2 } \times 15+ { x }^{ 2 }$$

Aromātai

$$6x^{3}+31x^{2}+4$$

Ngā Upane Otinga

Whakareatia te 2 ki te 15, ka 30.

$$6x^{3}+4+30x^{2}+x^{2}$$

Pahekotia te 30x^{2} me x^{2}, ka 31x^{2}.

$$6x^{3}+4+31x^{2}$$

Kimi Pārōnaki e ai ki x

$$2x\left(9x+31\right)$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Whakareatia te 2 ki te 15, ka 30.

$$\frac{\mathrm{d}}{\mathrm{d}x}(6x^{3}+4+30x^{2}+x^{2})$$

Pahekotia te 30x^{2} me x^{2}, ka 31x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(6x^{3}+4+31x^{2})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3\times 6x^{3-1}+2\times 31x^{2-1}$$

Whakareatia 3 ki te 6.

$$18x^{3-1}+2\times 31x^{2-1}$$

Tango 1 mai i 3.

$$18x^{2}+2\times 31x^{2-1}$$

Whakareatia 2 ki te 31.

$$18x^{2}+62x^{2-1}$$

Tango 1 mai i 2.

$$18x^{2}+62x^{1}$$

Mō tētahi kupu t, t^{1}=t.

$$18x^{2}+62x$$