Whakaoti i te 6x^2+4x-10=0

$$6 { x }^{ 2 } +4x-10=0$$

Whakaoti mō x

$$x = -\frac{5}{3} = -1\frac{2}{3} \approx -1.666666667$$

$$x=1$$

Ngā Upane Whakamahi Tauwehe Mā te Whakarōpū

Whakawehea ngā taha e rua ki te 2.

$$3x^{2}+2x-5=0$$

Hei whakaoti i te whārite, whakatauwehea te taha mauī mā te whakarōpū. Tuatahi, me tuhi anō te taha mauī hei 3x^{2}+ax+bx-5. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=2 ab=3\left(-5\right)=-15$$

I te mea kua tōraro te ab, he tauaro ngā tohu o a me b. I te mea kua tōrunga te a+b, he nui ake te uara pū o te tau tōrunga i tō te tōraro. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua -15.

$$-1,15 -3,5$$

Tātaihia te tapeke mō ia takirua.

$$-1+15=14 -3+5=2$$

Ko te otinga te takirua ka hoatu i te tapeke 2.

$$a=-3 b=5$$

Tuhia anō te 3x^{2}+2x-5 hei \left(3x^{2}-3x\right)+\left(5x-5\right).

$$\left(3x^{2}-3x\right)+\left(5x-5\right)$$

Tauwehea te 3x i te tuatahi me te 5 i te rōpū tuarua.

$$3x\left(x-1\right)+5\left(x-1\right)$$

Whakatauwehea atu te kīanga pātahi x-1 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(x-1\right)\left(3x+5\right)$$

Hei kimi otinga whārite, me whakaoti te x-1=0 me te 3x+5=0.

$$x=1 x=-\frac{5}{3}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$6x^{2}+4x-10=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 6 mō a, 4 mō b, me -10 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-4±\sqrt{4^{2}-4\times 6\left(-10\right)}}{2\times 6}$$

Pūrua 4.

$$x=\frac{-4±\sqrt{16-4\times 6\left(-10\right)}}{2\times 6}$$

Whakareatia -4 ki te 6.

$$x=\frac{-4±\sqrt{16-24\left(-10\right)}}{2\times 6}$$

Whakareatia -24 ki te -10.

$$x=\frac{-4±\sqrt{16+240}}{2\times 6}$$

Tāpiri 16 ki te 240.

$$x=\frac{-4±\sqrt{256}}{2\times 6}$$

Tuhia te pūtakerua o te 256.

$$x=\frac{-4±16}{2\times 6}$$

Whakareatia 2 ki te 6.

$$x=\frac{-4±16}{12}$$

Nā, me whakaoti te whārite x=\frac{-4±16}{12} ina he tāpiri te ±. Tāpiri -4 ki te 16.

$$x=\frac{12}{12}$$

Whakawehe 12 ki te 12.

$$x=1$$

Nā, me whakaoti te whārite x=\frac{-4±16}{12} ina he tango te ±. Tango 16 mai i -4.

$$x=-\frac{20}{12}$$

Whakahekea te hautanga \frac{-20}{12} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 4.

$$x=-\frac{5}{3}$$

Kua oti te whārite te whakatau.

$$x=1 x=-\frac{5}{3}$$

Ngā Upane mō te Whakaoti i te Pūrua

Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.

$$6x^{2}+4x-10=0$$

Me tāpiri 10 ki ngā taha e rua o te whārite.

$$6x^{2}+4x-10-\left(-10\right)=-\left(-10\right)$$

Mā te tango i te -10 i a ia ake anō ka toe ko te 0.

$$6x^{2}+4x=-\left(-10\right)$$

Tango -10 mai i 0.

$$6x^{2}+4x=10$$

Whakawehea ngā taha e rua ki te 6.

$$\frac{6x^{2}+4x}{6}=\frac{10}{6}$$

Mā te whakawehe ki te 6 ka wetekia te whakareanga ki te 6.

$$x^{2}+\frac{4}{6}x=\frac{10}{6}$$

Whakahekea te hautanga \frac{4}{6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x^{2}+\frac{2}{3}x=\frac{10}{6}$$

Whakahekea te hautanga \frac{10}{6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x^{2}+\frac{2}{3}x=\frac{5}{3}$$

Whakawehea te \frac{2}{3}, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te \frac{1}{3}. Nā, tāpiria te pūrua o te \frac{1}{3} ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$x^{2}+\frac{2}{3}x+\left(\frac{1}{3}\right)^{2}=\frac{5}{3}+\left(\frac{1}{3}\right)^{2}$$

Pūruatia \frac{1}{3} mā te pūrua i te taurunga me te tauraro o te hautanga.

$$x^{2}+\frac{2}{3}x+\frac{1}{9}=\frac{5}{3}+\frac{1}{9}$$

Tāpiri \frac{5}{3} ki te \frac{1}{9} mā te kimi i te tauraro pātahi me te tāpiri i ngā taurunga. Ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$x^{2}+\frac{2}{3}x+\frac{1}{9}=\frac{16}{9}$$

Tauwehea x^{2}+\frac{2}{3}x+\frac{1}{9}. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x+\frac{1}{3}\right)^{2}=\frac{16}{9}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x+\frac{1}{3}\right)^{2}}=\sqrt{\frac{16}{9}}$$

Whakarūnātia.

$$x+\frac{1}{3}=\frac{4}{3} x+\frac{1}{3}=-\frac{4}{3}$$

Me tango \frac{1}{3} mai i ngā taha e rua o te whārite.

$$x=1 x=-\frac{5}{3}$$