Whakaoti i te 6^3m+2=1

$$6 ^ { 3 m + 2 } = 1$$

Whakaoti mō m

$$m=-\frac{2}{3}\approx -0.666666667$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Taupū Kōaro

Whakamahia ngā ture taupū me ngā taupū kōaro hei whakaoti i te whārite.

$$6^{3m+2}=1$$

Tuhia te tau taupū kōaro o ngā taha e rua o te whārite.

$$\log(6^{3m+2})=\log(1)$$

Ko te taupū kōaro o tētahi tau ka hīkina ki tētahi pū ko te pū whakarea ki te taupū kōaro o taua tau.

$$\left(3m+2\right)\log(6)=\log(1)$$

Whakawehea ngā taha e rua ki te \log(6).

$$3m+2=\frac{\log(1)}{\log(6)}$$

Mā te tikanga tātai huri pūtake \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$3m+2=\log_{6}\left(1\right)$$

Me tango 2 mai i ngā taha e rua o te whārite.

$$3m=-2$$

Whakawehea ngā taha e rua ki te 3.

$$m=-\frac{2}{3}$$