Whakaoti i te 6^2+(16-x)^2=x^2

$$6 ^ { 2 } + ( 16 - x ) ^ { 2 } = x ^ { 2 }$$

Whakaoti mō x

$$x = \frac{73}{8} = 9\frac{1}{8} = 9.125$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te 6 mā te pū o 2, kia riro ko 36.

$$36+\left(16-x\right)^{2}=x^{2}$$

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(16-x\right)^{2}.

$$36+256-32x+x^{2}=x^{2}$$

Tāpirihia te 36 ki te 256, ka 292.

$$292-32x+x^{2}=x^{2}$$

Tangohia te x^{2} mai i ngā taha e rua.

$$292-32x+x^{2}-x^{2}=0$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$292-32x=0$$

Tangohia te 292 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-32x=-292$$

Whakawehea ngā taha e rua ki te -32.

$$x=\frac{-292}{-32}$$

Whakahekea te hautanga \frac{-292}{-32} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -4.

$$x=\frac{73}{8}$$