Whakaoti i te 6+8/x+2*4/x-2

$$6 + \frac { 8 } { x + 2 } \cdot \frac { 4 } { x - 2 }$$

Aromātai

$$\frac{2\left(3x^{2}+4\right)}{x^{2}-4}$$

Ngā Hipanga Rongoā Poto

Me whakarea te \frac{8}{x+2} ki te \frac{4}{x-2} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$6+\frac{8\times 4}{\left(x+2\right)\left(x-2\right)}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 6 ki te \frac{\left(x+2\right)\left(x-2\right)}{\left(x+2\right)\left(x-2\right)}.

$$\frac{6\left(x+2\right)\left(x-2\right)}{\left(x+2\right)\left(x-2\right)}+\frac{8\times 4}{\left(x+2\right)\left(x-2\right)}$$

Tā te mea he rite te tauraro o \frac{6\left(x+2\right)\left(x-2\right)}{\left(x+2\right)\left(x-2\right)} me \frac{8\times 4}{\left(x+2\right)\left(x-2\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{6\left(x+2\right)\left(x-2\right)+8\times 4}{\left(x+2\right)\left(x-2\right)}$$

Mahia ngā whakarea i roto o 6\left(x+2\right)\left(x-2\right)+8\times 4.

$$\frac{6x^{2}-12x+12x-24+32}{\left(x+2\right)\left(x-2\right)}$$

Whakakotahitia ngā kupu rite i 6x^{2}-12x+12x-24+32.

$$\frac{6x^{2}+8}{\left(x+2\right)\left(x-2\right)}$$

Whakarohaina te \left(x+2\right)\left(x-2\right).

$$\frac{6x^{2}+8}{x^{2}-4}$$

Tauwehe

$$\frac{2\left(3x^{2}+4\right)}{x^{2}-4}$$