Whakaoti i te 5x+1/2y=135/11

$$5x+ \frac{ 1 }{ 2 } y = \frac{ 135 }{ 11 }$$

Whakaoti mō x

$$x=-\frac{y}{10}+\frac{27}{11}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te \frac{1}{2}y mai i ngā taha e rua.

$$5x=\frac{135}{11}-\frac{1}{2}y$$

He hanga arowhānui tō te whārite.

$$5x=-\frac{y}{2}+\frac{135}{11}$$

Whakawehea ngā taha e rua ki te 5.

$$\frac{5x}{5}=\frac{-\frac{y}{2}+\frac{135}{11}}{5}$$

Mā te whakawehe ki te 5 ka wetekia te whakareanga ki te 5.

$$x=\frac{-\frac{y}{2}+\frac{135}{11}}{5}$$

Whakawehe \frac{135}{11}-\frac{y}{2} ki te 5.

$$x=-\frac{y}{10}+\frac{27}{11}$$

Whakaoti mō y

$$y=\frac{270}{11}-10x$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 5x mai i ngā taha e rua.

$$\frac{1}{2}y=\frac{135}{11}-5x$$

Me whakarea ngā taha e rua ki te 2.

$$\frac{\frac{1}{2}y}{\frac{1}{2}}=\frac{\frac{135}{11}-5x}{\frac{1}{2}}$$

Mā te whakawehe ki te \frac{1}{2} ka wetekia te whakareanga ki te \frac{1}{2}.

$$y=\frac{\frac{135}{11}-5x}{\frac{1}{2}}$$

Whakawehe \frac{135}{11}-5x ki te \frac{1}{2} mā te whakarea \frac{135}{11}-5x ki te tau huripoki o \frac{1}{2}.

$$y=\frac{270}{11}-10x$$