Whakaoti i te 50left(1-xright)^2=405

$$50 { \left(1-x \right) }^{ 2 } = 405$$

Whakaoti mō x

$$x=-\frac{9\sqrt{10}}{10}+1\approx -1.846049894$$

$$x=\frac{9\sqrt{10}}{10}+1\approx 3.846049894$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te 50.

$$\frac{50\left(-x+1\right)^{2}}{50}=\frac{405}{50}$$

Mā te whakawehe ki te 50 ka wetekia te whakareanga ki te 50.

$$\left(-x+1\right)^{2}=\frac{405}{50}$$

Whakahekea te hautanga \frac{405}{50} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 5.

$$\left(-x+1\right)^{2}=\frac{81}{10}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$-x+1=\frac{9\sqrt{10}}{10} -x+1=-\frac{9\sqrt{10}}{10}$$

Me tango 1 mai i ngā taha e rua o te whārite.

$$-x+1-1=\frac{9\sqrt{10}}{10}-1 -x+1-1=-\frac{9\sqrt{10}}{10}-1$$

Mā te tango i te 1 i a ia ake anō ka toe ko te 0.

$$-x=\frac{9\sqrt{10}}{10}-1 -x=-\frac{9\sqrt{10}}{10}-1$$

Tango 1 mai i \frac{9\sqrt{10}}{10}.

$$-x=\frac{9\sqrt{10}}{10}-1$$

Tango 1 mai i -\frac{9\sqrt{10}}{10}.

$$-x=-\frac{9\sqrt{10}}{10}-1$$

Whakawehea ngā taha e rua ki te -1.

$$\frac{-x}{-1}=\frac{\frac{9\sqrt{10}}{10}-1}{-1} \frac{-x}{-1}=\frac{-\frac{9\sqrt{10}}{10}-1}{-1}$$

Mā te whakawehe ki te -1 ka wetekia te whakareanga ki te -1.

$$x=\frac{\frac{9\sqrt{10}}{10}-1}{-1} x=\frac{-\frac{9\sqrt{10}}{10}-1}{-1}$$

Whakawehe \frac{9\sqrt{10}}{10}-1 ki te -1.

$$x=-\frac{9\sqrt{10}}{10}+1$$

Whakawehe -\frac{9\sqrt{10}}{10}-1 ki te -1.

$$x=\frac{9\sqrt{10}}{10}+1$$

Kua oti te whārite te whakatau.

$$x=-\frac{9\sqrt{10}}{10}+1 x=\frac{9\sqrt{10}}{10}+1$$