Whakaoti i te 50*(3-x^2)=100

$$50 \times ( 3 - x ^ { 2 } ) = 100$$

Whakaoti mō x

$$x=1$$

$$x=-1$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te 50.

$$3-x^{2}=\frac{100}{50}$$

Whakawehea te 100 ki te 50, kia riro ko 2.

$$3-x^{2}=2$$

Tangohia te 3 mai i ngā taha e rua.

$$-x^{2}=2-3$$

Tangohia te 3 i te 2, ka -1.

$$-x^{2}=-1$$

Whakawehea ngā taha e rua ki te -1.

$$x^{2}=\frac{-1}{-1}$$

Whakawehea te -1 ki te -1, kia riro ko 1.

$$x^{2}=1$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=1 x=-1$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawehea ngā taha e rua ki te 50.

$$3-x^{2}=\frac{100}{50}$$

Whakawehea te 100 ki te 50, kia riro ko 2.

$$3-x^{2}=2$$

Tangohia te 2 mai i ngā taha e rua.

$$3-x^{2}-2=0$$

Tangohia te 2 i te 3, ka 1.

$$1-x^{2}=0$$

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$-x^{2}+1=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi -1 mō a, 0 mō b, me 1 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-1\right)}}{2\left(-1\right)}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-1\right)}}{2\left(-1\right)}$$

Whakareatia -4 ki te -1.

$$x=\frac{0±\sqrt{4}}{2\left(-1\right)}$$

Tuhia te pūtakerua o te 4.

$$x=\frac{0±2}{2\left(-1\right)}$$

Whakareatia 2 ki te -1.

$$x=\frac{0±2}{-2}$$

Nā, me whakaoti te whārite x=\frac{0±2}{-2} ina he tāpiri te ±. Whakawehe 2 ki te -2.

$$x=-1$$

Nā, me whakaoti te whārite x=\frac{0±2}{-2} ina he tango te ±. Whakawehe -2 ki te -2.

$$x=1$$

Kua oti te whārite te whakatau.

$$x=-1 x=1$$