Whakaoti i te 5y^2-10y

$$5 y ^ { 2 } - 10 y$$

Tauwehe

$$5y\left(y-2\right)$$

Ngā Upane Otinga

Tauwehea te 5.

$$5\left(y^{2}-2y\right)$$

Whakaarohia te y^{2}-2y. Tauwehea te y.

$$y\left(y-2\right)$$

Me tuhi anō te kīanga whakatauwehe katoa.

$$5y\left(y-2\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$5y^{2}-10y=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$y=\frac{-\left(-10\right)±\sqrt{\left(-10\right)^{2}}}{2\times 5}$$

Tuhia te pūtakerua o te \left(-10\right)^{2}.

$$y=\frac{-\left(-10\right)±10}{2\times 5}$$

Ko te tauaro o -10 ko 10.

$$y=\frac{10±10}{2\times 5}$$

Whakareatia 2 ki te 5.

$$y=\frac{10±10}{10}$$

Nā, me whakaoti te whārite y=\frac{10±10}{10} ina he tāpiri te ±. Tāpiri 10 ki te 10.

$$y=\frac{20}{10}$$

Whakawehe 20 ki te 10.

$$y=2$$

Nā, me whakaoti te whārite y=\frac{10±10}{10} ina he tango te ±. Tango 10 mai i 10.

$$y=\frac{0}{10}$$

Whakawehe 0 ki te 10.

$$y=0$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te 2 mō te x_{1} me te 0 mō te x_{2}.

$$5y^{2}-10y=5\left(y-2\right)y$$

Aromātai

$$5y\left(y-2\right)$$