Whakaoti i te 5x*6x=x

$$5 x \cdot 6 x = x$$

Whakaoti mō x

$$x=\frac{1}{30}\approx 0.033333333$$

$$x=0$$

Ngā Upane Whakamahi Tauwehe

Whakareatia te x ki te x, ka x^{2}.

$$5x^{2}\times 6=x$$

Whakareatia te 5 ki te 6, ka 30.

$$30x^{2}=x$$

Tangohia te x mai i ngā taha e rua.

$$30x^{2}-x=0$$

Tauwehea te x.

$$x\left(30x-1\right)=0$$

Hei kimi otinga whārite, me whakaoti te x=0 me te 30x-1=0.

$$x=0 x=\frac{1}{30}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakareatia te x ki te x, ka x^{2}.

$$5x^{2}\times 6=x$$

Whakareatia te 5 ki te 6, ka 30.

$$30x^{2}=x$$

Tangohia te x mai i ngā taha e rua.

$$30x^{2}-x=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 30 mō a, -1 mō b, me 0 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-1\right)±\sqrt{1}}{2\times 30}$$

Tuhia te pūtakerua o te 1.

$$x=\frac{-\left(-1\right)±1}{2\times 30}$$

Ko te tauaro o -1 ko 1.

$$x=\frac{1±1}{2\times 30}$$

Whakareatia 2 ki te 30.

$$x=\frac{1±1}{60}$$

Nā, me whakaoti te whārite x=\frac{1±1}{60} ina he tāpiri te ±. Tāpiri 1 ki te 1.

$$x=\frac{2}{60}$$

Whakahekea te hautanga \frac{2}{60} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x=\frac{1}{30}$$

Nā, me whakaoti te whārite x=\frac{1±1}{60} ina he tango te ±. Tango 1 mai i 1.

$$x=\frac{0}{60}$$

Whakawehe 0 ki te 60.

$$x=0$$

Kua oti te whārite te whakatau.

$$x=\frac{1}{30} x=0$$

Ngā Upane mō te Whakaoti i te Pūrua

Whakareatia te x ki te x, ka x^{2}.

$$5x^{2}\times 6=x$$

Whakareatia te 5 ki te 6, ka 30.

$$30x^{2}=x$$

Tangohia te x mai i ngā taha e rua.

$$30x^{2}-x=0$$

Whakawehea ngā taha e rua ki te 30.

$$\frac{30x^{2}-x}{30}=\frac{0}{30}$$

Mā te whakawehe ki te 30 ka wetekia te whakareanga ki te 30.

$$x^{2}-\frac{1}{30}x=\frac{0}{30}$$

Whakawehe 0 ki te 30.

$$x^{2}-\frac{1}{30}x=0$$

Whakawehea te -\frac{1}{30}, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te -\frac{1}{60}. Nā, tāpiria te pūrua o te -\frac{1}{60} ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$x^{2}-\frac{1}{30}x+\left(-\frac{1}{60}\right)^{2}=\left(-\frac{1}{60}\right)^{2}$$

Pūruatia -\frac{1}{60} mā te pūrua i te taurunga me te tauraro o te hautanga.

$$x^{2}-\frac{1}{30}x+\frac{1}{3600}=\frac{1}{3600}$$

Tauwehea x^{2}-\frac{1}{30}x+\frac{1}{3600}. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{1}{60}\right)^{2}=\frac{1}{3600}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x-\frac{1}{60}\right)^{2}}=\sqrt{\frac{1}{3600}}$$

Whakarūnātia.

$$x-\frac{1}{60}=\frac{1}{60} x-\frac{1}{60}=-\frac{1}{60}$$

Me tāpiri \frac{1}{60} ki ngā taha e rua o te whārite.

$$x=\frac{1}{30} x=0$$