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5x^{2}-7x+1=0
Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.
x=\frac{-\left(-7\right)±\sqrt{\left(-7\right)^{2}-4\times 5}}{2\times 5}
Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 5 mō a, -7 mō b, me 1 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-7\right)±\sqrt{49-4\times 5}}{2\times 5}
Pūrua -7.
x=\frac{-\left(-7\right)±\sqrt{49-20}}{2\times 5}
Whakareatia -4 ki te 5.
x=\frac{-\left(-7\right)±\sqrt{29}}{2\times 5}
Tāpiri 49 ki te -20.
x=\frac{7±\sqrt{29}}{2\times 5}
Ko te tauaro o -7 ko 7.
x=\frac{7±\sqrt{29}}{10}
Whakareatia 2 ki te 5.
x=\frac{\sqrt{29}+7}{10}
Nā, me whakaoti te whārite x=\frac{7±\sqrt{29}}{10} ina he tāpiri te ±. Tāpiri 7 ki te \sqrt{29}.
x=\frac{7-\sqrt{29}}{10}
Nā, me whakaoti te whārite x=\frac{7±\sqrt{29}}{10} ina he tango te ±. Tango \sqrt{29} mai i 7.
x=\frac{\sqrt{29}+7}{10} x=\frac{7-\sqrt{29}}{10}
Kua oti te whārite te whakatau.
5x^{2}-7x+1=0
Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.
5x^{2}-7x+1-1=-1
Me tango 1 mai i ngā taha e rua o te whārite.
5x^{2}-7x=-1
Mā te tango i te 1 i a ia ake anō ka toe ko te 0.
\frac{5x^{2}-7x}{5}=-\frac{1}{5}
Whakawehea ngā taha e rua ki te 5.
x^{2}-\frac{7}{5}x=-\frac{1}{5}
Mā te whakawehe ki te 5 ka wetekia te whakareanga ki te 5.
x^{2}-\frac{7}{5}x+\left(-\frac{7}{10}\right)^{2}=-\frac{1}{5}+\left(-\frac{7}{10}\right)^{2}
Whakawehea te -\frac{7}{5}, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te -\frac{7}{10}. Nā, tāpiria te pūrua o te -\frac{7}{10} ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.
x^{2}-\frac{7}{5}x+\frac{49}{100}=-\frac{1}{5}+\frac{49}{100}
Pūruatia -\frac{7}{10} mā te pūrua i te taurunga me te tauraro o te hautanga.
x^{2}-\frac{7}{5}x+\frac{49}{100}=\frac{29}{100}
Tāpiri -\frac{1}{5} ki te \frac{49}{100} mā te kimi i te tauraro pātahi me te tāpiri i ngā taurunga. Ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.
\left(x-\frac{7}{10}\right)^{2}=\frac{29}{100}
Tauwehea x^{2}-\frac{7}{5}x+\frac{49}{100}. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{7}{10}\right)^{2}}=\sqrt{\frac{29}{100}}
Tuhia te pūtakerua o ngā taha e rua o te whārite.
x-\frac{7}{10}=\frac{\sqrt{29}}{10} x-\frac{7}{10}=-\frac{\sqrt{29}}{10}
Whakarūnātia.
x=\frac{\sqrt{29}+7}{10} x=\frac{7-\sqrt{29}}{10}
Me tāpiri \frac{7}{10} ki ngā taha e rua o te whārite.