Whakaoti i te 5x^2+4=8

$$5 x ^ { 2 } + 4 = 8$$

Whakaoti mō x

$$x=\frac{2\sqrt{5}}{5}\approx 0.894427191$$

$$x=-\frac{2\sqrt{5}}{5}\approx -0.894427191$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 4 mai i ngā taha e rua.

$$5x^{2}=8-4$$

Tangohia te 4 i te 8, ka 4.

$$5x^{2}=4$$

Whakawehea ngā taha e rua ki te 5.

$$x^{2}=\frac{4}{5}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{2\sqrt{5}}{5} x=-\frac{2\sqrt{5}}{5}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 8 mai i ngā taha e rua.

$$5x^{2}+4-8=0$$

Tangohia te 8 i te 4, ka -4.

$$5x^{2}-4=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 5 mō a, 0 mō b, me -4 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 5\left(-4\right)}}{2\times 5}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 5\left(-4\right)}}{2\times 5}$$

Whakareatia -4 ki te 5.

$$x=\frac{0±\sqrt{-20\left(-4\right)}}{2\times 5}$$

Whakareatia -20 ki te -4.

$$x=\frac{0±\sqrt{80}}{2\times 5}$$

Tuhia te pūtakerua o te 80.

$$x=\frac{0±4\sqrt{5}}{2\times 5}$$

Whakareatia 2 ki te 5.

$$x=\frac{0±4\sqrt{5}}{10}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{5}}{10} ina he tāpiri te ±.

$$x=\frac{2\sqrt{5}}{5}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{5}}{10} ina he tango te ±.

$$x=-\frac{2\sqrt{5}}{5}$$

Kua oti te whārite te whakatau.

$$x=\frac{2\sqrt{5}}{5} x=-\frac{2\sqrt{5}}{5}$$