Whakaoti i te 5x+5x^2+5

$$5 x + 5 x ^ { 2 } + 5$$

Tauwehe

$$5\left(x^{2}+x+1\right)$$

Ngā Upane Otinga

Tauwehea te 5. Kāore te pūrau x+x^{2}+1 i whakatauwehea i te mea kāhore ōna pūtake whakahau.

$$5\left(x+x^{2}+1\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$5x^{2}+5x+5=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-5±\sqrt{5^{2}-4\times 5\times 5}}{2\times 5}$$

Pūrua 5.

$$x=\frac{-5±\sqrt{25-4\times 5\times 5}}{2\times 5}$$

Whakareatia -4 ki te 5.

$$x=\frac{-5±\sqrt{25-20\times 5}}{2\times 5}$$

Whakareatia -20 ki te 5.

$$x=\frac{-5±\sqrt{25-100}}{2\times 5}$$

Tāpiri 25 ki te -100.

$$x=\frac{-5±\sqrt{-75}}{2\times 5}$$

Tā te mea e kore te pūrua o tētahi tau tōraro e tautohutia ki te āpure tūturu, kāhore he rongoā. Kāore e taea te pūrau pūrua te whakatauwehe.

$$5x^{2}+5x+5$$

Aromātai

$$5\left(x^{2}+x+1\right)$$