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\left(5x+3\right)^{2}=\left(\sqrt{3x+7}\right)^{2}
Pūruatia ngā taha e rua o te whārite.
25x^{2}+30x+9=\left(\sqrt{3x+7}\right)^{2}
Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(5x+3\right)^{2}.
25x^{2}+30x+9=3x+7
Tātaihia te \sqrt{3x+7} mā te pū o 2, kia riro ko 3x+7.
25x^{2}+30x+9-3x=7
Tangohia te 3x mai i ngā taha e rua.
25x^{2}+27x+9=7
Pahekotia te 30x me -3x, ka 27x.
25x^{2}+27x+9-7=0
Tangohia te 7 mai i ngā taha e rua.
25x^{2}+27x+2=0
Tangohia te 7 i te 9, ka 2.
a+b=27 ab=25\times 2=50
Hei whakaoti i te whārite, whakatauwehea te taha mauī mā te whakarōpū. Tuatahi, me tuhi anō te taha mauī hei 25x^{2}+ax+bx+2. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.
1,50 2,25 5,10
I te mea kua tōrunga te ab, he ōrite te tohu o a me b. I te mea kua tōrunga te a+b, he tōrunga hoki a a me b. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua 50.
1+50=51 2+25=27 5+10=15
Tātaihia te tapeke mō ia takirua.
a=2 b=25
Ko te otinga te takirua ka hoatu i te tapeke 27.
\left(25x^{2}+2x\right)+\left(25x+2\right)
Tuhia anō te 25x^{2}+27x+2 hei \left(25x^{2}+2x\right)+\left(25x+2\right).
x\left(25x+2\right)+25x+2
Whakatauwehea atu x i te 25x^{2}+2x.
\left(25x+2\right)\left(x+1\right)
Whakatauwehea atu te kīanga pātahi 25x+2 mā te whakamahi i te āhuatanga tātai tohatoha.
x=-\frac{2}{25} x=-1
Hei kimi otinga whārite, me whakaoti te 25x+2=0 me te x+1=0.
5\left(-\frac{2}{25}\right)+3=\sqrt{3\left(-\frac{2}{25}\right)+7}
Whakakapia te -\frac{2}{25} mō te x i te whārite 5x+3=\sqrt{3x+7}.
\frac{13}{5}=\frac{13}{5}
Whakarūnātia. Ko te uara x=-\frac{2}{25} kua ngata te whārite.
5\left(-1\right)+3=\sqrt{3\left(-1\right)+7}
Whakakapia te -1 mō te x i te whārite 5x+3=\sqrt{3x+7}.
-2=2
Whakarūnātia. Ko te uara x=-1 kāore e ngata ana ki te whārite nā te mea e rerekē ngā tohu o te taha maui me te taha katau.
x=-\frac{2}{25}
Ko te whārite 5x+3=\sqrt{3x+7} he rongoā ahurei.