Whakaoti i te 5m+sqrt{2z}=6

$$5 m + \sqrt { 2 z } = 6$$

Whakaoti mō m

$$m=\frac{-\sqrt{2z}+6}{5}$$

$$z\geq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te \sqrt{2z} mai i ngā taha e rua.

$$5m=6-\sqrt{2z}$$

He hanga arowhānui tō te whārite.

$$5m=-\sqrt{2z}+6$$

Whakawehea ngā taha e rua ki te 5.

$$\frac{5m}{5}=\frac{-\sqrt{2z}+6}{5}$$

Mā te whakawehe ki te 5 ka wetekia te whakareanga ki te 5.

$$m=\frac{-\sqrt{2z}+6}{5}$$

Whakaoti mō z

$$z=\frac{\left(6-5m\right)^{2}}{2}$$

$$6-5m\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Me tango 5m mai i ngā taha e rua o te whārite.

$$\sqrt{2z}+5m-5m=6-5m$$

Mā te tango i te 5m i a ia ake anō ka toe ko te 0.

$$\sqrt{2z}=6-5m$$

Pūruatia ngā taha e rua o te whārite.

$$2z=\left(6-5m\right)^{2}$$

Whakawehea ngā taha e rua ki te 2.

$$\frac{2z}{2}=\frac{\left(6-5m\right)^{2}}{2}$$

Mā te whakawehe ki te 2 ka wetekia te whakareanga ki te 2.

$$z=\frac{\left(6-5m\right)^{2}}{2}$$