Whakaoti i te 5a^2=45

$$5 a ^ { 2 } = 45$$

Whakaoti mō a

$$a=3$$

$$a=-3$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Whakawehea ngā taha e rua ki te 5.

$$a^{2}=\frac{45}{5}$$

Whakawehea te 45 ki te 5, kia riro ko 9.

$$a^{2}=9$$

Tangohia te 9 mai i ngā taha e rua.

$$a^{2}-9=0$$

Whakaarohia te a^{2}-9. Tuhia anō te a^{2}-9 hei a^{2}-3^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(a-3\right)\left(a+3\right)=0$$

Hei kimi otinga whārite, me whakaoti te a-3=0 me te a+3=0.

$$a=3 a=-3$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te 5.

$$a^{2}=\frac{45}{5}$$

Whakawehea te 45 ki te 5, kia riro ko 9.

$$a^{2}=9$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$a=3 a=-3$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawehea ngā taha e rua ki te 5.

$$a^{2}=\frac{45}{5}$$

Whakawehea te 45 ki te 5, kia riro ko 9.

$$a^{2}=9$$

Tangohia te 9 mai i ngā taha e rua.

$$a^{2}-9=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -9 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$a=\frac{0±\sqrt{0^{2}-4\left(-9\right)}}{2}$$

Pūrua 0.

$$a=\frac{0±\sqrt{-4\left(-9\right)}}{2}$$

Whakareatia -4 ki te -9.

$$a=\frac{0±\sqrt{36}}{2}$$

Tuhia te pūtakerua o te 36.

$$a=\frac{0±6}{2}$$

Nā, me whakaoti te whārite a=\frac{0±6}{2} ina he tāpiri te ±. Whakawehe 6 ki te 2.

$$a=3$$

Nā, me whakaoti te whārite a=\frac{0±6}{2} ina he tango te ±. Whakawehe -6 ki te 2.

$$a=-3$$

Kua oti te whārite te whakatau.

$$a=3 a=-3$$