Whakaoti i te 5-n^2+2sqrt{(5-n^2)(0)}

$$5 - n ^ { 2 } + 2 \sqrt { ( 5 - n ^ { 2 } ) ( 0 ) }$$

Aromātai

$$5-n^{2}$$

Ngā Upane Otinga

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$5-n^{2}+2\sqrt{0}$$

Tātaitia te pūtakerua o 0 kia tae ki 0.

$$5-n^{2}+2\times 0$$

Whakareatia te 2 ki te 0, ka 0.

$$5-n^{2}+0$$

Tāpirihia te 5 ki te 0, ka 5.

$$5-n^{2}$$

Kimi Pārōnaki e ai ki n

$$-2n$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$\frac{\mathrm{d}}{\mathrm{d}n}(5-n^{2}+2\sqrt{0})$$

Tātaitia te pūtakerua o 0 kia tae ki 0.

$$\frac{\mathrm{d}}{\mathrm{d}n}(5-n^{2}+2\times 0)$$

Whakareatia te 2 ki te 0, ka 0.

$$\frac{\mathrm{d}}{\mathrm{d}n}(5-n^{2}+0)$$

Tāpirihia te 5 ki te 0, ka 5.

$$\frac{\mathrm{d}}{\mathrm{d}n}(5-n^{2})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$2\left(-1\right)n^{2-1}$$

Whakareatia 2 ki te -1.

$$-2n^{2-1}$$

Tango 1 mai i 2.

$$-2n^{1}$$

Mō tētahi kupu t, t^{1}=t.

$$-2n$$