Whakaoti i te 5-3x^3-3x+1+2x^3+7x-13

$$5 - 3 x ^ { 3 } - 3 x + 1 + 2 x ^ { 3 } + 7 x - 13$$

Aromātai

$$-x^{3}+4x-7$$

Ngā Upane Otinga

Tāpirihia te 5 ki te 1, ka 6.

$$6-3x^{3}-3x+2x^{3}+7x-13$$

Pahekotia te -3x^{3} me 2x^{3}, ka -x^{3}.

$$6-x^{3}-3x+7x-13$$

Pahekotia te -3x me 7x, ka 4x.

$$6-x^{3}+4x-13$$

Tangohia te 13 i te 6, ka -7.

$$-7-x^{3}+4x$$

Kimi Pārōnaki e ai ki x

$$4-3x^{2}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Tāpirihia te 5 ki te 1, ka 6.

$$\frac{\mathrm{d}}{\mathrm{d}x}(6-3x^{3}-3x+2x^{3}+7x-13)$$

Pahekotia te -3x^{3} me 2x^{3}, ka -x^{3}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(6-x^{3}-3x+7x-13)$$

Pahekotia te -3x me 7x, ka 4x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(6-x^{3}+4x-13)$$

Tangohia te 13 i te 6, ka -7.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-7-x^{3}+4x)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3\left(-1\right)x^{3-1}+4x^{1-1}$$

Whakareatia 3 ki te -1.

$$-3x^{3-1}+4x^{1-1}$$

Tango 1 mai i 3.

$$-3x^{2}+4x^{1-1}$$

Tango 1 mai i 1.

$$-3x^{2}+4x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$-3x^{2}+4\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$-3x^{2}+4$$