Whakaoti i te 5(y-1/5)-2(6+y)=3(4y-5)+y

$$5 ( y - 1 / 5 ) - 2 ( 6 + y ) = 3 ( 4 y - 5 ) + y$$

Whakaoti mō y

$$y=\frac{1}{5}=0.2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 5 ki te y-\frac{1}{5}.

$$5y+5\left(-\frac{1}{5}\right)-2\left(6+y\right)=3\left(4y-5\right)+y$$

Me whakakore te 5 me te 5.

$$5y-1-2\left(6+y\right)=3\left(4y-5\right)+y$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te 6+y.

$$5y-1-12-2y=3\left(4y-5\right)+y$$

Tangohia te 12 i te -1, ka -13.

$$5y-13-2y=3\left(4y-5\right)+y$$

Pahekotia te 5y me -2y, ka 3y.

$$3y-13=3\left(4y-5\right)+y$$

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te 4y-5.

$$3y-13=12y-15+y$$

Pahekotia te 12y me y, ka 13y.

$$3y-13=13y-15$$

Tangohia te 13y mai i ngā taha e rua.

$$3y-13-13y=-15$$

Pahekotia te 3y me -13y, ka -10y.

$$-10y-13=-15$$

Me tāpiri te 13 ki ngā taha e rua.

$$-10y=-15+13$$

Tāpirihia te -15 ki te 13, ka -2.

$$-10y=-2$$

Whakawehea ngā taha e rua ki te -10.

$$y=\frac{-2}{-10}$$

Whakahekea te hautanga \frac{-2}{-10} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -2.

$$y=\frac{1}{5}$$