Whakaoti i te 5(x-3)+4(x+5)=20quad(x-7)

$$5 ( x - 3 ) + 4 ( x + 5 ) = 20 \quad ( x - 7 )$$

Whakaoti mō x

$$x = \frac{145}{11} = 13\frac{2}{11} \approx 13.181818182$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 5 ki te x-3.

$$5x-15+4\left(x+5\right)=20\left(x-7\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te x+5.

$$5x-15+4x+20=20\left(x-7\right)$$

Pahekotia te 5x me 4x, ka 9x.

$$9x-15+20=20\left(x-7\right)$$

Tāpirihia te -15 ki te 20, ka 5.

$$9x+5=20\left(x-7\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 20 ki te x-7.

$$9x+5=20x-140$$

Tangohia te 20x mai i ngā taha e rua.

$$9x+5-20x=-140$$

Pahekotia te 9x me -20x, ka -11x.

$$-11x+5=-140$$

Tangohia te 5 mai i ngā taha e rua.

$$-11x=-140-5$$

Tangohia te 5 i te -140, ka -145.

$$-11x=-145$$

Whakawehea ngā taha e rua ki te -11.

$$x=\frac{-145}{-11}$$

Ka taea te hautanga \frac{-145}{-11} te whakamāmā ki te \frac{145}{11} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$x=\frac{145}{11}$$