Whakaoti i te 5(x^2+4)=(x-2)[x+4(x-4)]

$$5 ( x ^ { 2 } + 4 ) = ( x - 2 ) [ x + 4 ( x - 4 ) ]$$

Whakaoti mō x

$$x=\frac{6}{13}\approx 0.461538462$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 5 ki te x^{2}+4.

$$5x^{2}+20=\left(x-2\right)\left(x+4\left(x-4\right)\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te x-4.

$$5x^{2}+20=\left(x-2\right)\left(x+4x-16\right)$$

Pahekotia te x me 4x, ka 5x.

$$5x^{2}+20=\left(x-2\right)\left(5x-16\right)$$

Whakamahia te āhuatanga tuaritanga hei whakarea te x-2 ki te 5x-16 ka whakakotahi i ngā kupu rite.

$$5x^{2}+20=5x^{2}-26x+32$$

Tangohia te 5x^{2} mai i ngā taha e rua.

$$5x^{2}+20-5x^{2}=-26x+32$$

Pahekotia te 5x^{2} me -5x^{2}, ka 0.

$$20=-26x+32$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-26x+32=20$$

Tangohia te 32 mai i ngā taha e rua.

$$-26x=20-32$$

Tangohia te 32 i te 20, ka -12.

$$-26x=-12$$

Whakawehea ngā taha e rua ki te -26.

$$x=\frac{-12}{-26}$$

Whakahekea te hautanga \frac{-12}{-26} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -2.

$$x=\frac{6}{13}$$