Whakaoti i te 5(x+2)-4(x-6)<8(x+3)

$$5 ( x + 2 ) - 4 ( x - 6 ) < 8 ( x + 3 )$$

Whakaoti mō x

$$x>\frac{10}{7}$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te 5 ki te x+2.

$$5x+10-4\left(x-6\right)<8\left(x+3\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -4 ki te x-6.

$$5x+10-4x+24<8\left(x+3\right)$$

Pahekotia te 5x me -4x, ka x.

$$x+10+24<8\left(x+3\right)$$

Tāpirihia te 10 ki te 24, ka 34.

$$x+34<8\left(x+3\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 8 ki te x+3.

$$x+34<8x+24$$

Tangohia te 8x mai i ngā taha e rua.

$$x+34-8x<24$$

Pahekotia te x me -8x, ka -7x.

$$-7x+34<24$$

Tangohia te 34 mai i ngā taha e rua.

$$-7x<24-34$$

Tangohia te 34 i te 24, ka -10.

$$-7x<-10$$

Whakawehea ngā taha e rua ki te -7. Nō te mea he <0 te -7, ka hurihia te ahunga koreōrite.

$$x>\frac{-10}{-7}$$

Ka taea te hautanga \frac{-10}{-7} te whakamāmā ki te \frac{10}{7} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$x>\frac{10}{7}$$