Whakaoti i te 5(5x+8-4)<3(8x+7-4)+(2x+6x-9)-8(4x-7)

$$5 ( 5 x + 8 - 4 ) < 3 ( 8 x + 7 - 4 ) + ( 2 x + 6 x - 9 ) - 8 ( 4 x - 7 )$$

Whakaoti mō x

$$x<\frac{36}{25}$$

Ngā Upane Otinga

Tangohia te 4 i te 8, ka 4.

$$5\left(5x+4\right)<3\left(8x+7-4\right)+2x+6x-9-8\left(4x-7\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 5 ki te 5x+4.

$$25x+20<3\left(8x+7-4\right)+2x+6x-9-8\left(4x-7\right)$$

Tangohia te 4 i te 7, ka 3.

$$25x+20<3\left(8x+3\right)+2x+6x-9-8\left(4x-7\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te 8x+3.

$$25x+20<24x+9+2x+6x-9-8\left(4x-7\right)$$

Pahekotia te 24x me 2x, ka 26x.

$$25x+20<26x+9+6x-9-8\left(4x-7\right)$$

Pahekotia te 26x me 6x, ka 32x.

$$25x+20<32x+9-9-8\left(4x-7\right)$$

Tangohia te 9 i te 9, ka 0.

$$25x+20<32x-8\left(4x-7\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -8 ki te 4x-7.

$$25x+20<32x-32x+56$$

Pahekotia te 32x me -32x, ka 0.

$$25x+20<56$$

Tangohia te 20 mai i ngā taha e rua.

$$25x<56-20$$

Tangohia te 20 i te 56, ka 36.

$$25x<36$$

Whakawehea ngā taha e rua ki te 25. Nō te mea he >0 te 25, ka noho pērā tonu te ahunga koreōrite.

$$x<\frac{36}{25}$$