Whakaoti i te 5(3^2-2^3)-sqrt{20-2^2}

$$5 ( 3 ^ { 2 } - 2 ^ { 3 } ) - \sqrt { 20 - 2 ^ { 2 } }$$

Aromātai

$$1$$

Ngā Upane Otinga

Tātaihia te 3 mā te pū o 2, kia riro ko 9.

$$5\left(9-2^{3}\right)-\sqrt{20-2^{2}}$$

Tātaihia te 2 mā te pū o 3, kia riro ko 8.

$$5\left(9-8\right)-\sqrt{20-2^{2}}$$

Tangohia te 8 i te 9, ka 1.

$$5\times 1-\sqrt{20-2^{2}}$$

Whakareatia te 5 ki te 1, ka 5.

$$5-\sqrt{20-2^{2}}$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$5-\sqrt{20-4}$$

Tangohia te 4 i te 20, ka 16.

$$5-\sqrt{16}$$

Tātaitia te pūtakerua o 16 kia tae ki 4.

$$5-4$$

Tangohia te 4 i te 5, ka 1.

$$1$$

Tauwehe

$$1$$