Whakaoti i te 5(2-3x)+4(3x+5)leq2(-x+1)

$$5 ( 2 - 3 x ) + 4 ( 3 x + 5 ) \leq 2 ( - x + 1 )$$

Whakaoti mō x

$$x\geq 28$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te 5 ki te 2-3x.

$$10-15x+4\left(3x+5\right)\leq 2\left(-x+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te 3x+5.

$$10-15x+12x+20\leq 2\left(-x+1\right)$$

Pahekotia te -15x me 12x, ka -3x.

$$10-3x+20\leq 2\left(-x+1\right)$$

Tāpirihia te 10 ki te 20, ka 30.

$$30-3x\leq 2\left(-x+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te -x+1.

$$30-3x\leq 2\left(-x\right)+2$$

Tangohia te 2\left(-x\right) mai i ngā taha e rua.

$$30-3x-2\left(-x\right)\leq 2$$

Whakareatia te -1 ki te 2, ka -2.

$$30-3x-2\left(-1\right)x\leq 2$$

Whakareatia te -2 ki te -1, ka 2.

$$30-3x+2x\leq 2$$

Pahekotia te -3x me 2x, ka -x.

$$30-x\leq 2$$

Tangohia te 30 mai i ngā taha e rua.

$$-x\leq 2-30$$

Tangohia te 30 i te 2, ka -28.

$$-x\leq -28$$

Whakawehea ngā taha e rua ki te -1. I te mea he tōraro a -1, ka huri te ahunga koreōrite.

$$x\geq \frac{-28}{-1}$$

Ka taea te hautanga \frac{-28}{-1} te whakamāmā ki te 28 mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$x\geq 28$$