Whakaoti i te 5x^2=3

$$5 { x }^{ 2 } =3$$

Whakaoti mō x

$$x=\frac{\sqrt{15}}{5}\approx 0.774596669$$

$$x=-\frac{\sqrt{15}}{5}\approx -0.774596669$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te 5.

$$x^{2}=\frac{3}{5}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{\sqrt{15}}{5} x=-\frac{\sqrt{15}}{5}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawehea ngā taha e rua ki te 5.

$$x^{2}=\frac{3}{5}$$

Tangohia te \frac{3}{5} mai i ngā taha e rua.

$$x^{2}-\frac{3}{5}=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -\frac{3}{5} mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-\frac{3}{5}\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-\frac{3}{5}\right)}}{2}$$

Whakareatia -4 ki te -\frac{3}{5}.

$$x=\frac{0±\sqrt{\frac{12}{5}}}{2}$$

Tuhia te pūtakerua o te \frac{12}{5}.

$$x=\frac{0±\frac{2\sqrt{15}}{5}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±\frac{2\sqrt{15}}{5}}{2} ina he tāpiri te ±.

$$x=\frac{\sqrt{15}}{5}$$

Nā, me whakaoti te whārite x=\frac{0±\frac{2\sqrt{15}}{5}}{2} ina he tango te ±.

$$x=-\frac{\sqrt{15}}{5}$$

Kua oti te whārite te whakatau.

$$x=\frac{\sqrt{15}}{5} x=-\frac{\sqrt{15}}{5}$$